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| Ord (int o) |
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| Ord (double o) |
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int | get_order () const |
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Ord | operator[] (const int nIndex) |
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Ord | operator+ (const Ord &o) |
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Ord | operator+ (double d) |
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Ord | operator+ (std::complex< double > d) |
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Ord | operator- (const Ord &o) |
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Ord | operator- (double d) |
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Ord | operator- (std::complex< double > d) |
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Ord | operator* (const Ord &o) |
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Ord | operator* (double d) |
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Ord | operator* (std::complex< double > d) |
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Ord | operator/ (const Ord &o) |
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Ord | operator/ (double d) |
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Ord | operator/ (std::complex< double > d) |
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Ord | operator+= (const Ord &o) |
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Ord | operator-= (const Ord &o) |
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Ord | operator+= (const double &d) |
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Ord | operator+= (const std::complex< double > &d) |
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Ord | operator-= (const double &d) |
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Ord | operator-= (const std::complex< double > &d) |
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Ord | operator*= (const double &d) |
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Ord | operator*= (const std::complex< double > &d) |
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Ord | operator/= (const double &d) |
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Ord | operator/= (const std::complex< double > &d) |
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bool | operator< (double d) |
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bool | operator< (std::complex< double > d) |
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bool | operator> (double d) |
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bool | operator> (std::complex< double > d) |
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bool | operator< (const Ord &o) |
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bool | operator> (const Ord &o) |
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Base type for orders of functions.
We defined a special arithmetics with this type to be able to analyze forms and determine the necessary integration order. This works for forms, but it also works for user-defined functions.
Definition at line 31 of file ord.h.